5(1+2m)=1/2)8+20m)

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Solution for 5(1+2m)=1/2)8+20m) equation: 



5(1+2m)=1/2)8+20m)

We move all terms to the left:

5(1+2m)-(1/2)8+20m))=0

We add all the numbers together, and all the variables

5(2m+1)+20m))-(+1/2)8=0

We multiply parentheses

10m+20m))-(+1/2)8+5=0

We multiply all the terms by the denominator


10m*2)8+5+20m))-(+1=0

Wy multiply elements

20m^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{40}=0$

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