5(1+2m)=1/28+20m)

Solution for 5(1+2m)=1/28+20m) equation:

5(1+2m)=1/28+20m)

We move all terms to the left:

5(1+2m)-(1/28+20m))=0


Domain of the equation: 28+20m))!=0

We move all terms containing m to the left, all other terms to the right

20m))!=-28

m!=-28/1

m!=-28

m∈R


We add all the numbers together, and all the variables

5(2m+1)-(+20m+1/28))=0

We multiply parentheses

10m-(+20m+1/28))+5=0

We multiply all the terms by the denominator


10m*28))+5-(+20m+1=0

Wy multiply elements

280m^2=0

a = 280; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·280·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{560}=0$