5(1+3b)+8b=-3b+7(4+7b)

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Solution for 5(1+3b)+8b=-3b+7(4+7b) equation: 



5(1+3b)+8b=-3b+7(4+7b)

We move all terms to the left:

5(1+3b)+8b-(-3b+7(4+7b))=0

We add all the numbers together, and all the variables

5(3b+1)+8b-(-3b+7(7b+4))=0

We add all the numbers together, and all the variables

8b+5(3b+1)-(-3b+7(7b+4))=0

We multiply parentheses

8b+15b-(-3b+7(7b+4))+5=0



We calculate terms in parentheses: -(-3b+7(7b+4)), so:

-3b+7(7b+4)

We multiply parentheses

-3b+49b+28

We add all the numbers together, and all the variables

46b+28

Back to the equation:

-(46b+28)



We add all the numbers together, and all the variables

23b-(46b+28)+5=0

We get rid of parentheses

23b-46b-28+5=0

We add all the numbers together, and all the variables

-23b-23=0

We move all terms containing b to the left, all other terms to the right

-23b=23

b=23/-23

b=-1

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