5(1+3b)=65

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Solution for 5(1+3b)=65 equation: 



5(1+3b)=65

We move all terms to the left:

5(1+3b)-(65)=0

We add all the numbers together, and all the variables

5(3b+1)-65=0

We multiply parentheses

15b+5-65=0

We add all the numbers together, and all the variables

15b-60=0

We move all terms containing b to the left, all other terms to the right

15b=60

b=60/15

b=4

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