5(1+4h)+2h=27h

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Solution for 5(1+4h)+2h=27h equation: 



5(1+4h)+2h=27h

We move all terms to the left:

5(1+4h)+2h-(27h)=0

We add all the numbers together, and all the variables

5(4h+1)+2h-27h=0

We add all the numbers together, and all the variables

-25h+5(4h+1)=0

We multiply parentheses

-25h+20h+5=0

We add all the numbers together, and all the variables

-5h+5=0

We move all terms containing h to the left, all other terms to the right

-5h=-5

h=-5/-5

h=1

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