5(1+4m)=2(3+0m)

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Solution for 5(1+4m)=2(3+0m) equation: 



5(1+4m)=2(3+0m)

We move all terms to the left:

5(1+4m)-(2(3+0m))=0

We add all the numbers together, and all the variables

5(4m+1)-(2(m+3))=0

We multiply parentheses

20m-(2(m+3))+5=0



We calculate terms in parentheses: -(2(m+3)), so:

2(m+3)

We multiply parentheses

2m+6

Back to the equation:

-(2m+6)



We get rid of parentheses

20m-2m-6+5=0

We add all the numbers together, and all the variables

18m-1=0

We move all terms containing m to the left, all other terms to the right

18m=1

m=1/18

m=1/18

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