5(1+4x)=-3(3-2x)

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Solution for 5(1+4x)=-3(3-2x) equation: 



5(1+4x)=-3(3-2x)

We move all terms to the left:

5(1+4x)-(-3(3-2x))=0

We add all the numbers together, and all the variables

5(4x+1)-(-3(-2x+3))=0

We multiply parentheses

20x-(-3(-2x+3))+5=0



We calculate terms in parentheses: -(-3(-2x+3)), so:

-3(-2x+3)

We multiply parentheses

6x-9

Back to the equation:

-(6x-9)



We get rid of parentheses

20x-6x+9+5=0

We add all the numbers together, and all the variables

14x+14=0

We move all terms containing x to the left, all other terms to the right

14x=-14

x=-14/14

x=-1

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