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5(1+4x)=4(3+5x)
We move all terms to the left:
5(1+4x)-(4(3+5x))=0
We add all the numbers together, and all the variables
5(4x+1)-(4(5x+3))=0
We multiply parentheses
20x-(4(5x+3))+5=0
We calculate terms in parentheses: -(4(5x+3)), so:We get rid of parentheses
4(5x+3)
We multiply parentheses
20x+12
Back to the equation:
-(20x+12)
20x-20x-12+5=0
We add all the numbers together, and all the variables
-7!=0
There is no solution for this equation
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