5(1+C)=4(c-1)

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Solution for 5(1+C)=4(c-1) equation:


Simplifying
5(1 + C) = 4(c + -1)
(1 * 5 + C * 5) = 4(c + -1)
(5 + 5C) = 4(c + -1)

Reorder the terms:
5 + 5C = 4(-1 + c)
5 + 5C = (-1 * 4 + c * 4)
5 + 5C = (-4 + 4c)

Solving
5 + 5C = -4 + 4c

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 5C = -4 + -5 + 4c

Combine like terms: 5 + -5 = 0
0 + 5C = -4 + -5 + 4c
5C = -4 + -5 + 4c

Combine like terms: -4 + -5 = -9
5C = -9 + 4c

Divide each side by '5'.
C = -1.8 + 0.8c

Simplifying
C = -1.8 + 0.8c

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