5(1+c)-2c+1=-3(2+c)

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Solution for 5(1+c)-2c+1=-3(2+c) equation: 



5(1+c)-2c+1=-3(2+c)

We move all terms to the left:

5(1+c)-2c+1-(-3(2+c))=0

We add all the numbers together, and all the variables

5(c+1)-2c-(-3(c+2))+1=0

We add all the numbers together, and all the variables

-2c+5(c+1)-(-3(c+2))+1=0

We multiply parentheses

-2c+5c-(-3(c+2))+5+1=0



We calculate terms in parentheses: -(-3(c+2)), so:

-3(c+2)

We multiply parentheses

-3c-6

Back to the equation:

-(-3c-6)



We add all the numbers together, and all the variables

3c-(-3c-6)+6=0

We get rid of parentheses

3c+3c+6+6=0

We add all the numbers together, and all the variables

6c+12=0

We move all terms containing c to the left, all other terms to the right

6c=-12

c=-12/6

c=-2

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