5(1+c)=6(2-c)

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Solution for 5(1+c)=6(2-c) equation:


Simplifying
5(1 + c) = 6(2 + -1c)
(1 * 5 + c * 5) = 6(2 + -1c)
(5 + 5c) = 6(2 + -1c)
5 + 5c = (2 * 6 + -1c * 6)
5 + 5c = (12 + -6c)

Solving
5 + 5c = 12 + -6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '6c' to each side of the equation.
5 + 5c + 6c = 12 + -6c + 6c

Combine like terms: 5c + 6c = 11c
5 + 11c = 12 + -6c + 6c

Combine like terms: -6c + 6c = 0
5 + 11c = 12 + 0
5 + 11c = 12

Add '-5' to each side of the equation.
5 + -5 + 11c = 12 + -5

Combine like terms: 5 + -5 = 0
0 + 11c = 12 + -5
11c = 12 + -5

Combine like terms: 12 + -5 = 7
11c = 7

Divide each side by '11'.
c = 0.6363636364

Simplifying
c = 0.6363636364

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