5(1+m)=6(m+1)-2m

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Solution for 5(1+m)=6(m+1)-2m equation: 



5(1+m)=6(m+1)-2m

We move all terms to the left:

5(1+m)-(6(m+1)-2m)=0

We add all the numbers together, and all the variables

5(m+1)-(6(m+1)-2m)=0

We multiply parentheses

5m-(6(m+1)-2m)+5=0



We calculate terms in parentheses: -(6(m+1)-2m), so:

6(m+1)-2m

We add all the numbers together, and all the variables

-2m+6(m+1)

We multiply parentheses

-2m+6m+6

We add all the numbers together, and all the variables

4m+6

Back to the equation:

-(4m+6)



We get rid of parentheses

5m-4m-6+5=0

We add all the numbers together, and all the variables

m-1=0

We move all terms containing m to the left, all other terms to the right

m=1

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