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5(1+z)=6(2+z)
We move all terms to the left:
5(1+z)-(6(2+z))=0
We add all the numbers together, and all the variables
5(z+1)-(6(z+2))=0
We multiply parentheses
5z-(6(z+2))+5=0
We calculate terms in parentheses: -(6(z+2)), so:We get rid of parentheses
6(z+2)
We multiply parentheses
6z+12
Back to the equation:
-(6z+12)
5z-6z-12+5=0
We add all the numbers together, and all the variables
-1z-7=0
We move all terms containing z to the left, all other terms to the right
-z=7
z=7/-1
z=-7
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