5(1-2b)=3(-5b+5)

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Solution for 5(1-2b)=3(-5b+5) equation: 



5(1-2b)=3(-5b+5)

We move all terms to the left:

5(1-2b)-(3(-5b+5))=0

We add all the numbers together, and all the variables

5(-2b+1)-(3(-5b+5))=0

We multiply parentheses

-10b-(3(-5b+5))+5=0



We calculate terms in parentheses: -(3(-5b+5)), so:

3(-5b+5)

We multiply parentheses

-15b+15

Back to the equation:

-(-15b+15)



We get rid of parentheses

-10b+15b-15+5=0

We add all the numbers together, and all the variables

5b-10=0

We move all terms containing b to the left, all other terms to the right

5b=10

b=10/5

b=2

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