5(1-2z)+7z-12=4(1-z)+z-11

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Solution for 5(1-2z)+7z-12=4(1-z)+z-11 equation: 


Simplifying
5(1 + -2z) + 7z + -12 = 4(1 + -1z) + z + -11
(1 * 5 + -2z * 5) + 7z + -12 = 4(1 + -1z) + z + -11
(5 + -10z) + 7z + -12 = 4(1 + -1z) + z + -11

Reorder the terms:
5 + -12 + -10z + 7z = 4(1 + -1z) + z + -11

Combine like terms: 5 + -12 = -7
-7 + -10z + 7z = 4(1 + -1z) + z + -11

Combine like terms: -10z + 7z = -3z
-7 + -3z = 4(1 + -1z) + z + -11
-7 + -3z = (1 * 4 + -1z * 4) + z + -11
-7 + -3z = (4 + -4z) + z + -11

Reorder the terms:
-7 + -3z = 4 + -11 + -4z + z

Combine like terms: 4 + -11 = -7
-7 + -3z = -7 + -4z + z

Combine like terms: -4z + z = -3z
-7 + -3z = -7 + -3z

Add '7' to each side of the equation.
-7 + 7 + -3z = -7 + 7 + -3z

Combine like terms: -7 + 7 = 0
0 + -3z = -7 + 7 + -3z
-3z = -7 + 7 + -3z

Combine like terms: -7 + 7 = 0
-3z = 0 + -3z
-3z = -3z

Add '3z' to each side of the equation.
-3z + 3z = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = -3z + 3z

Combine like terms: -3z + 3z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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