5(1-l)+10=2(l-9)-2

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Solution for 5(1-l)+10=2(l-9)-2 equation: 



5(1-l)+10=2(l-9)-2

We move all terms to the left:

5(1-l)+10-(2(l-9)-2)=0

We add all the numbers together, and all the variables

5(-1l+1)-(2(l-9)-2)+10=0

We multiply parentheses

-5l-(2(l-9)-2)+5+10=0



We calculate terms in parentheses: -(2(l-9)-2), so:

2(l-9)-2

We multiply parentheses

2l-18-2

We add all the numbers together, and all the variables

2l-20

Back to the equation:

-(2l-20)



We add all the numbers together, and all the variables

-5l-(2l-20)+15=0

We get rid of parentheses

-5l-2l+20+15=0

We add all the numbers together, and all the variables

-7l+35=0

We move all terms containing l to the left, all other terms to the right

-7l=-35

l=-35/-7

l=+5

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