5(1/5c)=7/2

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Solution for 5(1/5c)=7/2 equation: 



5(1/5c)=7/2

We move all terms to the left:

5(1/5c)-(7/2)=0



Domain of the equation: 5c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

5(+1/5c)-(+7/2)=0

We multiply parentheses

5c-(+7/2)=0

We get rid of parentheses

5c-7/2=0

We multiply all the terms by the denominator


5c*2-7=0

Wy multiply elements

10c-7=0

We move all terms containing c to the left, all other terms to the right

10c=7

c=7/10

c=7/10

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