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5(1/5x+3)=5(3/10x+4)
We move all terms to the left:
5(1/5x+3)-(5(3/10x+4))=0
Domain of the equation: 5x+3)!=0
x∈R
Domain of the equation: 10x+4))!=0We multiply parentheses
x∈R
5x-(5(3/10x+4))+15=0
We multiply all the terms by the denominator
5x*10x+15*10x+4))-(5(3+4))=0
We add all the numbers together, and all the variables
5x*10x+15*10x+4))-(57)=0
We add all the numbers together, and all the variables
5x*10x+15*10x=0
Wy multiply elements
50x^2+150x=0
a = 50; b = 150; c = 0;
Δ = b2-4ac
Δ = 1502-4·50·0
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(150)-150}{2*50}=\frac{-300}{100} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(150)+150}{2*50}=\frac{0}{100} =0 $
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