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5(10+x)=4(14+x)
We move all terms to the left:
5(10+x)-(4(14+x))=0
We add all the numbers together, and all the variables
5(x+10)-(4(x+14))=0
We multiply parentheses
5x-(4(x+14))+50=0
We calculate terms in parentheses: -(4(x+14)), so:We get rid of parentheses
4(x+14)
We multiply parentheses
4x+56
Back to the equation:
-(4x+56)
5x-4x-56+50=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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