5(10-3b)=105-3b+4(11-4b)

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Solution for 5(10-3b)=105-3b+4(11-4b) equation: 



5(10-3b)=105-3b+4(11-4b)

We move all terms to the left:

5(10-3b)-(105-3b+4(11-4b))=0

We add all the numbers together, and all the variables

5(-3b+10)-(105-3b+4(-4b+11))=0

We multiply parentheses

-15b-(105-3b+4(-4b+11))+50=0



We calculate terms in parentheses: -(105-3b+4(-4b+11)), so:

105-3b+4(-4b+11)

determiningTheFunctionDomain
-3b+4(-4b+11)+105

We multiply parentheses

-3b-16b+44+105

We add all the numbers together, and all the variables

-19b+149

Back to the equation:

-(-19b+149)



We get rid of parentheses

-15b+19b-149+50=0

We add all the numbers together, and all the variables

4b-99=0

We move all terms containing b to the left, all other terms to the right

4b=99

b=99/4

b=24+3/4

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