5(10-3b)=105-8b+4(11-44b)

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Solution for 5(10-3b)=105-8b+4(11-44b) equation: 



5(10-3b)=105-8b+4(11-44b)

We move all terms to the left:

5(10-3b)-(105-8b+4(11-44b))=0

We add all the numbers together, and all the variables

5(-3b+10)-(105-8b+4(-44b+11))=0

We multiply parentheses

-15b-(105-8b+4(-44b+11))+50=0



We calculate terms in parentheses: -(105-8b+4(-44b+11)), so:

105-8b+4(-44b+11)

determiningTheFunctionDomain
-8b+4(-44b+11)+105

We multiply parentheses

-8b-176b+44+105

We add all the numbers together, and all the variables

-184b+149

Back to the equation:

-(-184b+149)



We get rid of parentheses

-15b+184b-149+50=0

We add all the numbers together, and all the variables

169b-99=0

We move all terms containing b to the left, all other terms to the right

169b=99

b=99/169

b=99/169

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