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5(10-x)=6(13-2x)
We move all terms to the left:
5(10-x)-(6(13-2x))=0
We add all the numbers together, and all the variables
5(-1x+10)-(6(-2x+13))=0
We multiply parentheses
-5x-(6(-2x+13))+50=0
We calculate terms in parentheses: -(6(-2x+13)), so:We get rid of parentheses
6(-2x+13)
We multiply parentheses
-12x+78
Back to the equation:
-(-12x+78)
-5x+12x-78+50=0
We add all the numbers together, and all the variables
7x-28=0
We move all terms containing x to the left, all other terms to the right
7x=28
x=28/7
x=4
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