5(10x+1)+2(2x+3)+1=9(x+20)+10(x+1)-3

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Solution for 5(10x+1)+2(2x+3)+1=9(x+20)+10(x+1)-3 equation: 



5(10x+1)+2(2x+3)+1=9(x+20)+10(x+1)-3

We move all terms to the left:

5(10x+1)+2(2x+3)+1-(9(x+20)+10(x+1)-3)=0

We multiply parentheses

50x+4x-(9(x+20)+10(x+1)-3)+5+6+1=0



We calculate terms in parentheses: -(9(x+20)+10(x+1)-3), so:

9(x+20)+10(x+1)-3

We multiply parentheses

9x+10x+180+10-3

We add all the numbers together, and all the variables

19x+187

Back to the equation:

-(19x+187)



We add all the numbers together, and all the variables

54x-(19x+187)+12=0

We get rid of parentheses

54x-19x-187+12=0

We add all the numbers together, and all the variables

35x-175=0

We move all terms containing x to the left, all other terms to the right

35x=175

x=175/35

x=5

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