5(10x+12)=-40(x-3)

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Solution for 5(10x+12)=-40(x-3) equation: 



5(10x+12)=-40(x-3)

We move all terms to the left:

5(10x+12)-(-40(x-3))=0

We multiply parentheses

50x-(-40(x-3))+60=0



We calculate terms in parentheses: -(-40(x-3)), so:

-40(x-3)

We multiply parentheses

-40x+120

Back to the equation:

-(-40x+120)



We get rid of parentheses

50x+40x-120+60=0

We add all the numbers together, and all the variables

90x-60=0

We move all terms containing x to the left, all other terms to the right

90x=60

x=60/90

x=2/3

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