5(11+2b)+4b=27

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Solution for 5(11+2b)+4b=27 equation: 



5(11+2b)+4b=27

We move all terms to the left:

5(11+2b)+4b-(27)=0

We add all the numbers together, and all the variables

5(2b+11)+4b-27=0

We add all the numbers together, and all the variables

4b+5(2b+11)-27=0

We multiply parentheses

4b+10b+55-27=0

We add all the numbers together, and all the variables

14b+28=0

We move all terms containing b to the left, all other terms to the right

14b=-28

b=-28/14

b=-2

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