5(12-)+9=28+7x+(3x-4)

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Solution for 5(12-)+9=28+7x+(3x-4) equation: 



5(12-)+9=28+7x+(3x-4)

We move all terms to the left:

5(12-)+9-(28+7x+(3x-4))=0

We add all the numbers together, and all the variables

-(28+7x+(3x-4))+9+50=0

We add all the numbers together, and all the variables

-(28+7x+(3x-4))+59=0



We calculate terms in parentheses: -(28+7x+(3x-4)), so:

28+7x+(3x-4)

determiningTheFunctionDomain
7x+(3x-4)+28

We get rid of parentheses

7x+3x-4+28

We add all the numbers together, and all the variables

10x+24

Back to the equation:

-(10x+24)



We get rid of parentheses

-10x-24+59=0

We add all the numbers together, and all the variables

-10x+35=0

We move all terms containing x to the left, all other terms to the right

-10x=-35

x=-35/-10

x=3+1/2

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