5(12-2x)+7x=4(3x-2)-11x-8

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Solution for 5(12-2x)+7x=4(3x-2)-11x-8 equation: 



5(12-2x)+7x=4(3x-2)-11x-8

We move all terms to the left:

5(12-2x)+7x-(4(3x-2)-11x-8)=0

We add all the numbers together, and all the variables

5(-2x+12)+7x-(4(3x-2)-11x-8)=0

We add all the numbers together, and all the variables

7x+5(-2x+12)-(4(3x-2)-11x-8)=0

We multiply parentheses

7x-10x-(4(3x-2)-11x-8)+60=0



We calculate terms in parentheses: -(4(3x-2)-11x-8), so:

4(3x-2)-11x-8

We add all the numbers together, and all the variables

-11x+4(3x-2)-8

We multiply parentheses

-11x+12x-8-8

We add all the numbers together, and all the variables

x-16

Back to the equation:

-(x-16)



We add all the numbers together, and all the variables

-3x-(x-16)+60=0

We get rid of parentheses

-3x-x+16+60=0

We add all the numbers together, and all the variables

-4x+76=0

We move all terms containing x to the left, all other terms to the right

-4x=-76

x=-76/-4

x=+19

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