5(12-3y)+7y=8(3y-2)-13y

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Solution for 5(12-3y)+7y=8(3y-2)-13y equation: 



5(12-3y)+7y=8(3y-2)-13y

We move all terms to the left:

5(12-3y)+7y-(8(3y-2)-13y)=0

We add all the numbers together, and all the variables

5(-3y+12)+7y-(8(3y-2)-13y)=0

We add all the numbers together, and all the variables

7y+5(-3y+12)-(8(3y-2)-13y)=0

We multiply parentheses

7y-15y-(8(3y-2)-13y)+60=0



We calculate terms in parentheses: -(8(3y-2)-13y), so:

8(3y-2)-13y

We add all the numbers together, and all the variables

-13y+8(3y-2)

We multiply parentheses

-13y+24y-16

We add all the numbers together, and all the variables

11y-16

Back to the equation:

-(11y-16)



We add all the numbers together, and all the variables

-8y-(11y-16)+60=0

We get rid of parentheses

-8y-11y+16+60=0

We add all the numbers together, and all the variables

-19y+76=0

We move all terms containing y to the left, all other terms to the right

-19y=-76

y=-76/-19

y=+4

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