5(12-x)+9=28+7x+(3x-4)

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Solution for 5(12-x)+9=28+7x+(3x-4) equation: 



5(12-x)+9=28+7x+(3x-4)

We move all terms to the left:

5(12-x)+9-(28+7x+(3x-4))=0

We add all the numbers together, and all the variables

5(-1x+12)-(28+7x+(3x-4))+9=0

We multiply parentheses

-5x-(28+7x+(3x-4))+60+9=0



We calculate terms in parentheses: -(28+7x+(3x-4)), so:

28+7x+(3x-4)

determiningTheFunctionDomain
7x+(3x-4)+28

We get rid of parentheses

7x+3x-4+28

We add all the numbers together, and all the variables

10x+24

Back to the equation:

-(10x+24)



We add all the numbers together, and all the variables

-5x-(10x+24)+69=0

We get rid of parentheses

-5x-10x-24+69=0

We add all the numbers together, and all the variables

-15x+45=0

We move all terms containing x to the left, all other terms to the right

-15x=-45

x=-45/-15

x=+3

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