5(12-x)+9x=28+7x+(3x-4)

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Solution for 5(12-x)+9x=28+7x+(3x-4) equation: 



5(12-x)+9x=28+7x+(3x-4)

We move all terms to the left:

5(12-x)+9x-(28+7x+(3x-4))=0

We add all the numbers together, and all the variables

5(-1x+12)+9x-(28+7x+(3x-4))=0

We add all the numbers together, and all the variables

9x+5(-1x+12)-(28+7x+(3x-4))=0

We multiply parentheses

9x-5x-(28+7x+(3x-4))+60=0



We calculate terms in parentheses: -(28+7x+(3x-4)), so:

28+7x+(3x-4)

determiningTheFunctionDomain
7x+(3x-4)+28

We get rid of parentheses

7x+3x-4+28

We add all the numbers together, and all the variables

10x+24

Back to the equation:

-(10x+24)



We add all the numbers together, and all the variables

4x-(10x+24)+60=0

We get rid of parentheses

4x-10x-24+60=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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