5(14z-2)=9(z-20)-13

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Solution for 5(14z-2)=9(z-20)-13 equation: 



5(14z-2)=9(z-20)-13

We move all terms to the left:

5(14z-2)-(9(z-20)-13)=0

We multiply parentheses

70z-(9(z-20)-13)-10=0



We calculate terms in parentheses: -(9(z-20)-13), so:

9(z-20)-13

We multiply parentheses

9z-180-13

We add all the numbers together, and all the variables

9z-193

Back to the equation:

-(9z-193)



We get rid of parentheses

70z-9z+193-10=0

We add all the numbers together, and all the variables

61z+183=0

We move all terms containing z to the left, all other terms to the right

61z=-183

z=-183/61

z=-3

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