5(1=t)=2(2t-1)=12

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Solution for 5(1=t)=2(2t-1)=12 equation: 



5(1=t)=2(2t-1)=12

We move all terms to the left:

5(1-(t))=0

We add all the numbers together, and all the variables

5(-1t+1)=0

We multiply parentheses

-5t+5=0

We move all terms containing t to the left, all other terms to the right

-5t=-5

t=-5/-5

t=1

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