5(1d-4)+2=2(1d+2)-4

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Solution for 5(1d-4)+2=2(1d+2)-4 equation:


Simplifying
5(1d + -4) + 2 = 2(1d + 2) + -4

Reorder the terms:
5(-4 + 1d) + 2 = 2(1d + 2) + -4
(-4 * 5 + 1d * 5) + 2 = 2(1d + 2) + -4
(-20 + 5d) + 2 = 2(1d + 2) + -4

Reorder the terms:
-20 + 2 + 5d = 2(1d + 2) + -4

Combine like terms: -20 + 2 = -18
-18 + 5d = 2(1d + 2) + -4

Reorder the terms:
-18 + 5d = 2(2 + 1d) + -4
-18 + 5d = (2 * 2 + 1d * 2) + -4
-18 + 5d = (4 + 2d) + -4

Reorder the terms:
-18 + 5d = 4 + -4 + 2d

Combine like terms: 4 + -4 = 0
-18 + 5d = 0 + 2d
-18 + 5d = 2d

Solving
-18 + 5d = 2d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2d' to each side of the equation.
-18 + 5d + -2d = 2d + -2d

Combine like terms: 5d + -2d = 3d
-18 + 3d = 2d + -2d

Combine like terms: 2d + -2d = 0
-18 + 3d = 0

Add '18' to each side of the equation.
-18 + 18 + 3d = 0 + 18

Combine like terms: -18 + 18 = 0
0 + 3d = 0 + 18
3d = 0 + 18

Combine like terms: 0 + 18 = 18
3d = 18

Divide each side by '3'.
d = 6

Simplifying
d = 6

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