5(1x-3)+2x=41

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Solution for 5(1x-3)+2x=41 equation:



5(1x-3)+2x=41
We move all terms to the left:
5(1x-3)+2x-(41)=0
We add all the numbers together, and all the variables
5(x-3)+2x-41=0
We add all the numbers together, and all the variables
2x+5(x-3)-41=0
We multiply parentheses
2x+5x-15-41=0
We add all the numbers together, and all the variables
7x-56=0
We move all terms containing x to the left, all other terms to the right
7x=56
x=56/7
x=8

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