5(1y+2)=6(1y+-7)

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Solution for 5(1y+2)=6(1y+-7) equation:


Simplifying
5(1y + 2) = 6(1y + -7)

Reorder the terms:
5(2 + 1y) = 6(1y + -7)
(2 * 5 + 1y * 5) = 6(1y + -7)
(10 + 5y) = 6(1y + -7)

Reorder the terms:
10 + 5y = 6(-7 + 1y)
10 + 5y = (-7 * 6 + 1y * 6)
10 + 5y = (-42 + 6y)

Solving
10 + 5y = -42 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
10 + 5y + -6y = -42 + 6y + -6y

Combine like terms: 5y + -6y = -1y
10 + -1y = -42 + 6y + -6y

Combine like terms: 6y + -6y = 0
10 + -1y = -42 + 0
10 + -1y = -42

Add '-10' to each side of the equation.
10 + -10 + -1y = -42 + -10

Combine like terms: 10 + -10 = 0
0 + -1y = -42 + -10
-1y = -42 + -10

Combine like terms: -42 + -10 = -52
-1y = -52

Divide each side by '-1'.
y = 52

Simplifying
y = 52

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