5(2(k)-3)=2(7(k)+4)

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Solution for 5(2(k)-3)=2(7(k)+4) equation: 



5(2(k)-3)=2(7(k)+4)

We move all terms to the left:

5(2(k)-3)-(2(7(k)+4))=0

We multiply parentheses

10k-(2(7k+4))-15=0



We calculate terms in parentheses: -(2(7k+4)), so:

2(7k+4)

We multiply parentheses

14k+8

Back to the equation:

-(14k+8)



We get rid of parentheses

10k-14k-8-15=0

We add all the numbers together, and all the variables

-4k-23=0

We move all terms containing k to the left, all other terms to the right

-4k=23

k=23/-4

k=-5+3/4

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