5(2(k-5))=3(4(k+2))

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Solution for 5(2(k-5))=3(4(k+2)) equation:


Simplifying
5(2(k + -5)) = 3(4(k + 2))

Reorder the terms:
5(2(-5 + k)) = 3(4(k + 2))
5((-5 * 2 + k * 2)) = 3(4(k + 2))
5((-10 + 2k)) = 3(4(k + 2))
(-10 * 5 + 2k * 5) = 3(4(k + 2))
(-50 + 10k) = 3(4(k + 2))

Reorder the terms:
-50 + 10k = 3(4(2 + k))
-50 + 10k = 3((2 * 4 + k * 4))
-50 + 10k = 3((8 + 4k))
-50 + 10k = (8 * 3 + 4k * 3)
-50 + 10k = (24 + 12k)

Solving
-50 + 10k = 24 + 12k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-12k' to each side of the equation.
-50 + 10k + -12k = 24 + 12k + -12k

Combine like terms: 10k + -12k = -2k
-50 + -2k = 24 + 12k + -12k

Combine like terms: 12k + -12k = 0
-50 + -2k = 24 + 0
-50 + -2k = 24

Add '50' to each side of the equation.
-50 + 50 + -2k = 24 + 50

Combine like terms: -50 + 50 = 0
0 + -2k = 24 + 50
-2k = 24 + 50

Combine like terms: 24 + 50 = 74
-2k = 74

Divide each side by '-2'.
k = -37

Simplifying
k = -37

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