5(2+)-w=10+4(w+1)

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Solution for 5(2+)-w=10+4(w+1) equation:



5(2+)-w=10+4(w+1)
We move all terms to the left:
5(2+)-w-(10+4(w+1))=0
We add all the numbers together, and all the variables
-w-(10+4(w+1))+50=0
We add all the numbers together, and all the variables
-1w-(10+4(w+1))+50=0
We calculate terms in parentheses: -(10+4(w+1)), so:
10+4(w+1)
determiningTheFunctionDomain 4(w+1)+10
We multiply parentheses
4w+4+10
We add all the numbers together, and all the variables
4w+14
Back to the equation:
-(4w+14)
We get rid of parentheses
-1w-4w-14+50=0
We add all the numbers together, and all the variables
-5w+36=0
We move all terms containing w to the left, all other terms to the right
-5w=-36
w=-36/-5
w=7+1/5

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