5(2+-0.6y)=10-3y

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Solution for 5(2+-0.6y)=10-3y equation: 



5(2+-0.6y)=10-3y

We move all terms to the left:

5(2+-0.6y)-(10-3y)=0

We add all the numbers together, and all the variables

5(-0.6y)-(-3y+10)=0

We multiply parentheses

0y-(-3y+10)=0

We get rid of parentheses

0y+3y-10=0

We add all the numbers together, and all the variables

4y-10=0

We move all terms containing y to the left, all other terms to the right

4y=10

y=10/4

y=2+1/2

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