5(2+1)=3(z+2)+11

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Solution for 5(2+1)=3(z+2)+11 equation: 



5(2+1)=3(z+2)+11

We move all terms to the left:

5(2+1)-(3(z+2)+11)=0

We add all the numbers together, and all the variables

-(3(z+2)+11)+53=0



We calculate terms in parentheses: -(3(z+2)+11), so:

3(z+2)+11

We multiply parentheses

3z+6+11

We add all the numbers together, and all the variables

3z+17

Back to the equation:

-(3z+17)



We get rid of parentheses

-3z-17+53=0

We add all the numbers together, and all the variables

-3z+36=0

We move all terms containing z to the left, all other terms to the right

-3z=-36

z=-36/-3

z=+12

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