5(2+2c)=6(3c-2)

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Solution for 5(2+2c)=6(3c-2) equation:


Simplifying
5(2 + 2c) = 6(3c + -2)
(2 * 5 + 2c * 5) = 6(3c + -2)
(10 + 10c) = 6(3c + -2)

Reorder the terms:
10 + 10c = 6(-2 + 3c)
10 + 10c = (-2 * 6 + 3c * 6)
10 + 10c = (-12 + 18c)

Solving
10 + 10c = -12 + 18c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-18c' to each side of the equation.
10 + 10c + -18c = -12 + 18c + -18c

Combine like terms: 10c + -18c = -8c
10 + -8c = -12 + 18c + -18c

Combine like terms: 18c + -18c = 0
10 + -8c = -12 + 0
10 + -8c = -12

Add '-10' to each side of the equation.
10 + -10 + -8c = -12 + -10

Combine like terms: 10 + -10 = 0
0 + -8c = -12 + -10
-8c = -12 + -10

Combine like terms: -12 + -10 = -22
-8c = -22

Divide each side by '-8'.
c = 2.75

Simplifying
c = 2.75

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