5(2+2r)=-4(3-2r)+2

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Solution for 5(2+2r)=-4(3-2r)+2 equation: 



5(2+2r)=-4(3-2r)+2

We move all terms to the left:

5(2+2r)-(-4(3-2r)+2)=0

We add all the numbers together, and all the variables

5(2r+2)-(-4(-2r+3)+2)=0

We multiply parentheses

10r-(-4(-2r+3)+2)+10=0



We calculate terms in parentheses: -(-4(-2r+3)+2), so:

-4(-2r+3)+2

We multiply parentheses

8r-12+2

We add all the numbers together, and all the variables

8r-10

Back to the equation:

-(8r-10)



We get rid of parentheses

10r-8r+10+10=0

We add all the numbers together, and all the variables

2r+20=0

We move all terms containing r to the left, all other terms to the right

2r=-20

r=-20/2

r=-10

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