5(2+5)-v=10+4(v+1)

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Solution for 5(2+5)-v=10+4(v+1) equation: 



5(2+5)-v=10+4(v+1)

We move all terms to the left:

5(2+5)-v-(10+4(v+1))=0

We add all the numbers together, and all the variables

-v-(10+4(v+1))+57=0

We add all the numbers together, and all the variables

-1v-(10+4(v+1))+57=0



We calculate terms in parentheses: -(10+4(v+1)), so:

10+4(v+1)

determiningTheFunctionDomain
4(v+1)+10

We multiply parentheses

4v+4+10

We add all the numbers together, and all the variables

4v+14

Back to the equation:

-(4v+14)



We get rid of parentheses

-1v-4v-14+57=0

We add all the numbers together, and all the variables

-5v+43=0

We move all terms containing v to the left, all other terms to the right

-5v=-43

v=-43/-5

v=8+3/5

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