5(2+5b)=15-(b-7)

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Solution for 5(2+5b)=15-(b-7) equation: 



5(2+5b)=15-(b-7)

We move all terms to the left:

5(2+5b)-(15-(b-7))=0

We add all the numbers together, and all the variables

5(5b+2)-(15-(b-7))=0

We multiply parentheses

25b-(15-(b-7))+10=0



We calculate terms in parentheses: -(15-(b-7)), so:

15-(b-7)

determiningTheFunctionDomain
-(b-7)+15

We get rid of parentheses

-b+7+15

We add all the numbers together, and all the variables

-1b+22

Back to the equation:

-(-1b+22)



We get rid of parentheses

25b+1b-22+10=0

We add all the numbers together, and all the variables

26b-12=0

We move all terms containing b to the left, all other terms to the right

26b=12

b=12/26

b=6/13

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