5(2+c)=4(c-1)

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Solution for 5(2+c)=4(c-1) equation:


Simplifying
5(2 + c) = 4(c + -1)
(2 * 5 + c * 5) = 4(c + -1)
(10 + 5c) = 4(c + -1)

Reorder the terms:
10 + 5c = 4(-1 + c)
10 + 5c = (-1 * 4 + c * 4)
10 + 5c = (-4 + 4c)

Solving
10 + 5c = -4 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
10 + 5c + -4c = -4 + 4c + -4c

Combine like terms: 5c + -4c = 1c
10 + 1c = -4 + 4c + -4c

Combine like terms: 4c + -4c = 0
10 + 1c = -4 + 0
10 + 1c = -4

Add '-10' to each side of the equation.
10 + -10 + 1c = -4 + -10

Combine like terms: 10 + -10 = 0
0 + 1c = -4 + -10
1c = -4 + -10

Combine like terms: -4 + -10 = -14
1c = -14

Divide each side by '1'.
c = -14

Simplifying
c = -14

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