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5(2+c)=45+5c=
We move all terms to the left:
5(2+c)-(45+5c)=0
We add all the numbers together, and all the variables
5(c+2)-(5c+45)=0
We multiply parentheses
5c-(5c+45)+10=0
We get rid of parentheses
5c-5c-45+10=0
We add all the numbers together, and all the variables
-35!=0
There is no solution for this equation
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