5(2+u)+u=10+4(u+1)

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Solution for 5(2+u)+u=10+4(u+1) equation: 



5(2+u)+u=10+4(u+1)

We move all terms to the left:

5(2+u)+u-(10+4(u+1))=0

We add all the numbers together, and all the variables

5(u+2)+u-(10+4(u+1))=0

We add all the numbers together, and all the variables

u+5(u+2)-(10+4(u+1))=0

We multiply parentheses

u+5u-(10+4(u+1))+10=0



We calculate terms in parentheses: -(10+4(u+1)), so:

10+4(u+1)

determiningTheFunctionDomain
4(u+1)+10

We multiply parentheses

4u+4+10

We add all the numbers together, and all the variables

4u+14

Back to the equation:

-(4u+14)



We add all the numbers together, and all the variables

6u-(4u+14)+10=0

We get rid of parentheses

6u-4u-14+10=0

We add all the numbers together, and all the variables

2u-4=0

We move all terms containing u to the left, all other terms to the right

2u=4

u=4/2

u=2

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