5(2+w)-w=10+3(w+1)

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Solution for 5(2+w)-w=10+3(w+1) equation: 



5(2+w)-w=10+3(w+1)

We move all terms to the left:

5(2+w)-w-(10+3(w+1))=0

We add all the numbers together, and all the variables

5(w+2)-w-(10+3(w+1))=0

We add all the numbers together, and all the variables

-1w+5(w+2)-(10+3(w+1))=0

We multiply parentheses

-1w+5w-(10+3(w+1))+10=0



We calculate terms in parentheses: -(10+3(w+1)), so:

10+3(w+1)

determiningTheFunctionDomain
3(w+1)+10

We multiply parentheses

3w+3+10

We add all the numbers together, and all the variables

3w+13

Back to the equation:

-(3w+13)



We add all the numbers together, and all the variables

4w-(3w+13)+10=0

We get rid of parentheses

4w-3w-13+10=0

We add all the numbers together, and all the variables

w-3=0

We move all terms containing w to the left, all other terms to the right

w=3

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