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5(2+w)-w=10+4(w+4)
We move all terms to the left:
5(2+w)-w-(10+4(w+4))=0
We add all the numbers together, and all the variables
5(w+2)-w-(10+4(w+4))=0
We add all the numbers together, and all the variables
-1w+5(w+2)-(10+4(w+4))=0
We multiply parentheses
-1w+5w-(10+4(w+4))+10=0
We calculate terms in parentheses: -(10+4(w+4)), so:We add all the numbers together, and all the variables
10+4(w+4)
determiningTheFunctionDomain 4(w+4)+10
We multiply parentheses
4w+16+10
We add all the numbers together, and all the variables
4w+26
Back to the equation:
-(4w+26)
4w-(4w+26)+10=0
We get rid of parentheses
4w-4w-26+10=0
We add all the numbers together, and all the variables
-16!=0
There is no solution for this equation
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