5(2+w)-w=10+4(w-1)

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Solution for 5(2+w)-w=10+4(w-1) equation: 



5(2+w)-w=10+4(w-1)

We move all terms to the left:

5(2+w)-w-(10+4(w-1))=0

We add all the numbers together, and all the variables

5(w+2)-w-(10+4(w-1))=0

We add all the numbers together, and all the variables

-1w+5(w+2)-(10+4(w-1))=0

We multiply parentheses

-1w+5w-(10+4(w-1))+10=0



We calculate terms in parentheses: -(10+4(w-1)), so:

10+4(w-1)

determiningTheFunctionDomain
4(w-1)+10

We multiply parentheses

4w-4+10

We add all the numbers together, and all the variables

4w+6

Back to the equation:

-(4w+6)



We add all the numbers together, and all the variables

4w-(4w+6)+10=0

We get rid of parentheses

4w-4w-6+10=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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